If the motors are identical, in series, they both take the same current. Effectively, they both use the same voltage, which, as they are identical, is half the supply each. If one of the motors is more heavily loade (stiffer bearings etc) it will lose some impedance, drop the voltage across itself, leave a bit more for its mate, and its mate, now having more power to play with, will work harder. Like Dave says, a set of problems and heartache waiting to happen.
As for current flow theory, just stick with the old water analogy, with positive being higher, and the water running downhill. Worked well for me for thirty-odd years and saved a lot of confusion when sorting diagrams. If you can trace a path from + to -, without either going back on yourself or taking a short cut, you have a circuit. If it goes through the components intended, probably a good circuit.